Solve for x: log 3 (x + 1) - 1 = 3 + log 3 (x - 1)

Given, log 3 (x + 1) - 1 = 3 + log 3 (x - 1) Since log 3 3 = 1, the above equation can be written as ⇒ log 3 (x + 1) - log 3 3 = 3log 3 3 + log 3 (x - 1) ⇒ log 3 (x + 1) - log 3 3 = log 3 3 3 + log 3 (x - 1) ⇒ ⇒ ⇒ ⇒ x + 1 = 81(x - 1) ⇒ x + 1 = 81x - 81 ⇒ 81x - x = 1 + 81 ⇒ 80x = 82 ⇒ x = Hence, x = .

Solve the following equation:
log₁₀(x + 2) + log₁₀(x - 2) = log₁₀3 + 3log₁₀4

View Answer Bookmark Now

Solve the following equation:
log(3x + 2) + log(3x - 2) = 5log 2

View Answer Bookmark Now

Solve for x: 5^{log x} + 3^{log x} = 3^{log x + 1} - 5^{log x - 1}.

View Answer Bookmark Now

Mathematics

Solve for x: log₃(x + 1) - 1 = 3 + log₃(x - 1)

Logarithms

Related Questions

Solve the following equation:
log₁₀(x + 2) + log₁₀(x - 2) = log₁₀3 + 3log₁₀4

Solve the following equation:
log(3x + 2) + log(3x - 2) = 5log 2

Solve for x: 5^{log x} + 3^{log x} = 3^{log x + 1} - 5^{log x - 1}.

Mathematics

Solve for x: log3(x + 1) - 1 = 3 + log3(x - 1)

Logarithms

Related Questions

Solve the following equation:log10(x + 2) + log10(x - 2) = log103 + 3log104

Solve the following equation:log(3x + 2) + log(3x - 2) = 5log 2

Solve for x: 5log x + 3log x = 3log x + 1 - 5log x - 1.

Solve for x: log₃(x + 1) - 1 = 3 + log₃(x - 1)

Solve the following equation:
log₁₀(x + 2) + log₁₀(x - 2) = log₁₀3 + 3log₁₀4

Solve the following equation:
log(3x + 2) + log(3x - 2) = 5log 2

Solve for x: 5^{log x} + 3^{log x} = 3^{log x + 1} - 5^{log x - 1}.