Solve the following equation:

log₁₀(x + 2) + log₁₀(x - 2) = log₁₀3 + 3log₁₀4

Given,

⇒ log₁₀ (x + 2) + log₁₀ (x - 2) = log₁₀ 3 + 3log₁₀ 4

⇒ log₁₀ (x + 2)(x - 2) = log₁₀ 3 + log₁₀ 4³

⇒ log₁₀ (x² - 4) = log₁₀ 3 + log₁₀ 64

⇒ log₁₀ (x² - 4) = log₁₀ (3 × 64)

⇒ log₁₀ (x² - 4) = log₁₀ 192

⇒ x² - 4 = 192

⇒ x² = 196

⇒ x = $\sqrt{196}$ = 14.

Hence, x = 14.