Solve for x using the quadratic formula. Write your answer correct to two significant figures.

(x - 1)² - 3x + 4 = 0

Given,

⇒ (x - 1)² - 3x + 4 = 0

⇒ x² + 1 - 2x - 3x + 4 = 0

⇒ x² - 5x + 5 = 0

Comparing x² - 5x + 5 = 0 with ax² + bx + c = 0 we get,

a = 1, b = -5 and c = 5.

We know that,

x = $\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Substituting values of a, b and c in above equation we get,

$\Rightarrow x = \dfrac{-(-5) \pm \sqrt{(-5)^2 - 4.(1).(5)}}{2(1)} \\[1em] = \dfrac{5 \pm \sqrt{25 - 20}}{2} \\[1em] = \dfrac{5 \pm \sqrt{5}}{2} \\[1em] = \dfrac{5 \pm 2.2}{2} \\[1em] = \dfrac{5 + 2.2}{2} \text{ or } \dfrac{5 - 2.2}{2} \\[1em] = \dfrac{7.2}{2} \text{ or } \dfrac{2.8}{2} \\[1em] = 3.6 \text{ or } 1.4$

Hence, x = 3.6 or 1.4