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Mathematics

Solve, graphically, the following pairs of equations :

(i)

x - 5 = 0
y + 4 = 0

(ii)

2x + y = 23
4x - y = 19

(iii)

3x + 7y = 27

8y=52x8 - y = \dfrac{5}{2}x

(iv)

x+14=23(12y)\dfrac{x + 1}{4} = \dfrac{2}{3}(1 - 2y)

2+5y3=x72\dfrac{2 + 5y}{3} = \dfrac{x}{7} - 2

Graphical Solution

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Answer

(i) x - 5 = 0

⇒ x = 5

and, y + 4 = 0

⇒ y = - 4

Solve, graphically, the following pairs of equations : Graphical Solution, Concise Mathematics Solutions ICSE Class 9.

On the same graph paper, draw the graph for each given equation.

Both the straight lines drawn meet at point P. As it is clear from the graph, co-ordinates of the common point are (5, -4).

Solution of the given equations is : x = 5 and y = -4.

(ii)

First equation : 2x + y = 23

Step 1:

Give at least three suitable values to the variable x and find the corresponding values of y.

Let x = 2, then 2 ×\times 2 + y = 23 ⇒ y = 19

Let x = 4, then 2 ×\times 4 + y = 23 ⇒ y = 15

Let x = 6, then 2 ×\times 6 + y = 23 ⇒ y = 11

Step 2:

Make a table (as given below) for the different pairs of the values of x and y:

x246
y191511

Step 3:

Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph.

Second equation : 4x - y = 19

Step 1:

Give at least three suitable values to the variable x and find the corresponding values of y.

Let x = 4, then 4 ×\times 4 - y = 19 ⇒ y = -3

Let x = 6, then 4 ×\times 6 - y = 19 ⇒ y = 5

Let x = 8, then 4 ×\times 8 - y = 19 ⇒ y = 13

Step 2:

Make a table (as given below) for the different pairs of the values of x and y:

x468
y-3513

Step 3:

Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph.

Solve, graphically, the following pairs of equations : Graphical Solution, Concise Mathematics Solutions ICSE Class 9.

On the same graph paper, draw the graph for each given equation.

Both the straight lines drawn meet at point P. As it is clear from the graph, co-ordinates of the common point are (7, 9).

Solution of the given equations is : x = 7 and y = 9.

(iii)

First equation : 3x + 7y = 27

Step 1:

Give at least three suitable values to the variable x and find the corresponding values of y.

Let x = 0, then 3 ×\times 0 + 7y = 27 ⇒ y = 3.8

Let x = 2, then 3 ×\times 2 + 7y = 27 ⇒ y = 3

Let x = 4, then 3 ×\times 4 + 7y = 27 ⇒ y = 2.1

Step 2:

Make a table (as given below) for the different pairs of the values of x and y:

x024
y3.832.1

Step 3:

Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph.

Second equation : 8y=52x8 - y = \dfrac{5}{2}x

Step 1:

Give at least three suitable values to the variable x and find the corresponding values of y.

Let x = 0, then 8y=52×08 - y = \dfrac{5}{2} \times 0 ⇒ y = 8

Let x = 1, then 8y=52×18 - y = \dfrac{5}{2} \times 1 ⇒ y = 5.5

Let x = 2, then 8y=52×28 - y = \dfrac{5}{2} \times 2 ⇒ y = 3

Step 2:

Make a table (as given below) for the different pairs of the values of x and y:

x012
y85.53

Step 3:

Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph.

Solve, graphically, the following pairs of equations : Graphical Solution, Concise Mathematics Solutions ICSE Class 9.

On the same graph paper, draw the graph for each given equation.

Both the straight lines drawn meet at point P. As it is clear from the graph, co-ordinates of the common point are (2, 3).

Solution of the given equations is : x = 2 and y = 3.

(iv)

First equation : x+14=23(12y)\dfrac{x + 1}{4} = \dfrac{2}{3}(1 - 2y)

Step 1:

Give at least three suitable values to the variable x and find the corresponding values of y.

Let x = 0, then 0+14=23(12y)\dfrac{0 + 1}{4} = \dfrac{2}{3}(1 - 2y) ⇒ y = 0.3

Let x = 3, then 3+14=23(12y)\dfrac{3 + 1}{4} = \dfrac{2}{3}(1 - 2y) ⇒ y = -0.2

Let x = 7, then 7+14=23(12y)\dfrac{7 + 1}{4} = \dfrac{2}{3}(1 - 2y) ⇒ y = -1

Step 2:

Make a table (as given below) for the different pairs of the values of x and y:

x037
y0.3-0.2-1

Step 3:

Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph.

Second equation : 2+5y3=x72\dfrac{2 + 5y}{3} = \dfrac{x}{7} - 2

Step 1:

Give at least three suitable values to the variable x and find the corresponding values of y.

Let x = 0, then 2+5y3=072\dfrac{2 + 5y}{3} = \dfrac{0}{7} - 2 ⇒ y = -1.6

Let x = 7, then 2+5y3=772\dfrac{2 + 5y}{3} = \dfrac{7}{7} - 2 ⇒ y = -1

Let x = 14, then 2+5y3=1472\dfrac{2 + 5y}{3} = \dfrac{14}{7} - 2 ⇒ y = -0.4

Step 2:

Make a table (as given below) for the different pairs of the values of x and y:

x0714
y-1.6-1-0.4

Step 3:

Plot the points, from the table, on a graph paper and then draw a straight line passing through the points plotted on the graph.

Solve, graphically, the following pairs of equations : Graphical Solution, Concise Mathematics Solutions ICSE Class 9.

On the same graph paper, draw the graph for each given equation.

Both the straight lines drawn meet at point P. As it is clear from the graph, co-ordinates of the common point are (7, -1).

Solution of the given equations is : x = 7 and y = -1.

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