Solve (question no. 2-22) for x : 3x/x + 6 - x/x + 5 = 2

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KnowledgeBoat · Accepted Answer

Since L.C.M. of denominators (x \+ 6) and (x \+ 5) = (x \+ 6)(x \+ 5), multiply each term with (x \+ 6)(x \+ 5) to get: ⇒ 3x(x \+ 5) \- x(x \+ 6) = 2(x \+ 6)(x \+ 5) ⇒ (3x² \+ 15x) \- (x² \+ 6x) = 2(x² \+ 6x \+ 5x \+ 30) ⇒ 3x² \+ 15x \- x² \- 6x = 2(x² \+ 11x \+ 30) ⇒ 2x² \+ 9x = 2x² \+ 22x \+ 60 ⇒ 2x² \- 2x² \+ 9x \- 22x = 60 ⇒ -13x = 60 ⇒ x = - ⇒ x = - Hence, the value of x is .

Mathematics

Solve (question no. 2-22) for x : 3x/x + 6 - x/x + 5 = 2

Linear Eqns One Variable

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Solve (question no. 2-22) for x : 3x/x + 6 - x/x + 5 = 2

Linear Eqns One Variable

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