Solve the following equation:

$3x - \dfrac{8}{x} = 2$

Given, $3x - \dfrac{8}{x} = 2$.

By taking L.C.M. we get,

$\Rightarrow \dfrac{3x^2 - 8}{x} = 2$

By cross multiplication we get,

⇒ 3x² - 8 = 2x

⇒ 3x² - 2x - 8 = 0

⇒ 3x² - 6x + 4x - 8 = 0

⇒ 3x(x - 2) + 4(x - 2) = 0

⇒ (3x + 4)(x - 2) = 0

⇒ 3x + 4 = 0 or x - 2 = 0

⇒ 3x = -4 or x = 2

⇒ x = $-\dfrac{4}{3}$ or x = 2.

Hence, roots of the given equations are 2, $-\dfrac{4}{3}$.