Solve the following equation:

6x + 29 = $\dfrac{5}{x}$

Given, 6x + 29 = $\dfrac{5}{x}$.

By cross multiplication,

⇒ x(6x + 29) = 5

⇒ 6x² + 29x = 5

⇒ 6x² + 29x - 5 = 0

⇒ 6x² + 30x - x - 5 = 0

⇒ 6x(x + 5) - 1(x + 5) = 0

⇒ (6x - 1)(x + 5) = 0

⇒ 6x - 1 = 0 or x + 5 = 0

⇒ 6x = 1 or x = -5

⇒ x = $\dfrac{1}{6}$ or x = -5.

Hence, roots of the given equations are -5, $\dfrac{1}{6}$.