Solve the following equation for x: log^2(x^2 - 1) = 3

Given, ⇒ = 3 ⇒ x 2 - 1 = 2 3 ⇒ x 2 - 1 = 8 ⇒ x 2 = 9 ⇒ x = . Hence, x = ±3.

Mathematics

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Given,

⇒ $\text{log}_2(x^2 - 1)$ = 3

⇒ x² - 1 = 2³

⇒ x² - 1 = 8

⇒ x² = 9

⇒ x = $\sqrt{9} = \pm3$ .

Hence, x = ±3.

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