Solve the following equation for x:
log7 (2x2 - 1) = 2
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Given,
⇒ log7 (2x2 - 1) = 2
⇒ 2x2 - 1 = 72
⇒ 2x2 - 1 = 49
⇒ 2x2 = 50
⇒ x2 = 25
⇒ x = 5, -5.
Hence, x = 5, -5.
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log4 32 = x - 4
log (x2 - 21) = 2
log6 (x - 2)(x + 3) = 1