Solve : $\dfrac{x}{2} > -1 + \dfrac{3x}{4}; x ∈ N$

Solve : $\dfrac{2}{3}x + 5 ≤ \dfrac{1}{2}x + 6; x ∈ W$

Solve $\dfrac{2}{3} (x - 1) + 4 < 10$ and represent its solution on a number line. Given the replacement set is {-8, -6, -4, 3, 6, 8, 12}.

If x is a whole number and 12 - x > 3x - 5; the solution set is:

1. {1, 2, 3, 4}

2. {1, 2, 3, 4, 5}

3. {0, 1, 2, 3, 4, 5}

4. {0, 1, 2, 3, 4,}