Solve : $\dfrac{x}{2} > -1 + \dfrac{3x}{4}; x ∈ N$

$\dfrac{x}{2} > -1 + \dfrac{3x}{4}$

⇒ $\dfrac{x}{2} - \dfrac{3x}{4} > -1$

Since L.C.M. of denominator 2 and 4 = 4, multiply each term with 4 to get:

⇒ $\dfrac{4 \times x}{2} - \dfrac{4 \times 3x}{4} > -4 \times 1$

⇒ 2x - 3x > - 4

⇒ - 1x > - 4

⇒ x < 4

∵ x is a natural number.

Hence, solution set = {1, 2, 3}.