Solve : $\dfrac{2x}{5}$ + 1 < - 3; x ∈ R

$\dfrac{2x}{5}$ + 1 < - 3

⇒ $\dfrac{2x}{5}$ < - 3 - 1

⇒ $\dfrac{2x}{5}$ < - 4

By cross multiplying, we get

⇒ x < - $\dfrac{5 \times 4}{2}$

⇒ x < - $\dfrac{20}{2}$

⇒ x < - 10

∵ x is a real number.