Solve : $\dfrac{2x + 3}{5} > \dfrac{4x - 1}{2}$, x ∈ W.

$\dfrac{2x + 3}{5} > \dfrac{4x - 1}{2}$

By cross multiplying, we get

⇒ 2(2x + 3) > 5(4x - 1)

⇒ 4x + 6 > 20x - 5

⇒ 5 + 6 > 20x - 4x

⇒ 11 > 16x

⇒ $\dfrac{11}{16}$ > x

⇒ 0.6875 > x

∵ x is a whole number.

Hence, solution set = {0}.