Solve: where x is a positive odd integer.

Given, Since, x is a positive odd integer Hence, x = {1, 3, 5}.

Mathematics

Solve:
$\dfrac{x}{2} + 5 \le \dfrac{x}{3} + 6$ where x is a positive odd integer.

Linear Inequations

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Answer

Given,

$\dfrac{x}{2} +5 \le \dfrac{x}{3} + 6\\[0.5em] \Rightarrow \dfrac{x}{2} - \dfrac{x}{3} \le 6-5\\[0.5em] \Rightarrow \dfrac{3x-2x}{6} \le 1\\[0.5em] \Rightarrow \dfrac{x}{6} \le 1\\[0.5em] \Rightarrow x \le 6$

Since, x is a positive odd integer
Hence, x = {1, 3, 5}.

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Mathematics

Solve:
$\dfrac{x}{2} + 5 \le \dfrac{x}{3} + 6$ where x is a positive odd integer.

Linear Inequations

Answer

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Solve:
$\dfrac{x}{2} + 5 \le \dfrac{x}{3} + 6$ where x is a positive odd integer.

Find the values of x, which satisfy the inequation:
$−2 \le \dfrac{1}{2}-\dfrac{2x}{3} \le 1\dfrac{5}{6}$ , x ∈ N.
Graph the solution set on the number line.

If x ∈ W, find the solution set of $\dfrac{3}{5} x - \dfrac{2x−1}{3} \gt$ 1. Also graph the solution set on the number line, if possible.

Solve:
$\dfrac{2x+3}{3} \ge \dfrac{3x−1}{4}$ where x is positive even integer.

Given that x ∈ I, solve the inequation and graph the solution on the number line :
$3 \ge \dfrac{x−4}{2} + \dfrac{x}{3} \ge 2$