Solve for x :
log xlog 5=log 9log (13)\dfrac{\log \space x}{\log \space 5} = \dfrac{\log \space 9}{\log \space \Big(\dfrac{1}{3}\Big)}log 5log x=log (31)log 9
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Given,
⇒log xlog 5=log 9log (13)⇒log xlog 5=log 32log 3−1⇒log xlog 5=2log 3−1log 3⇒log xlog 5=−2⇒log x=−2×log 5⇒log x=log 5−2⇒log x=log (125)⇒x=125.\Rightarrow \dfrac{\log \space x}{\log \space 5} = \dfrac{\log \space 9}{\log \space \Big(\dfrac{1}{3}\Big)} \\[1em] \Rightarrow \dfrac{\log \space x}{\log \space 5} = \dfrac{\log \space 3^2}{\log \space 3 ^{-1}} \\[1em] \Rightarrow \dfrac{\log \space x}{\log \space 5} = \dfrac{2\log \space 3}{-1\log \space 3} \\[1em] \Rightarrow \dfrac{\log \space x}{\log \space 5} = -2 \\[1em] \Rightarrow \log \space x = -2 \times \log \space 5 \\[1em] \Rightarrow \log \space x = \log \space 5 ^{-2} \\[1em] \Rightarrow \log \space x = \log \space \Big(\dfrac{1}{25}\Big) \\[1em] \Rightarrow x = \dfrac{1}{25}.⇒log 5log x=log (31)log 9⇒log 5log x=log 3−1log 32⇒log 5log x=−1log 32log 3⇒log 5log x=−2⇒log x=−2×log 5⇒log x=log 5−2⇒log x=log (251)⇒x=251.
Hence, the value of x = 125\dfrac{1}{25}251.
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log (x2 − 21) = 2
2 log x + 1 = log 250
If (log 7−log 2+log 16−2log 3−log 745)=1+log n\Big(\log \space 7 - \log \space 2 + \log \space 16 - 2 \log \space 3 - \log \space \dfrac{7}{45}\Big) = 1 + \log \space n(log 7−log 2+log 16−2log 3−log 457)=1+log n, find the value of n.
Write the logarithmic equation for :
R=3VπhR = \dfrac{3V}{\sqrt{\pi h}}R=πh3V