Mathematics
Statement 1: The graph of 2x - 5 = 0 is a line parallel to y-axis.
Statement 2: When the equations of line are of the form x = ± k (a constant), the lines are parallel to y-axis.
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Graphical Solution
2 Likes
Answer
Given,
⇒ 2x - 5 = 0
⇒ 2x = 5
⇒ x =
This represents a vertical line (parallel to the y-axis) at a distance of units.
This line is at a distance of units to the right of the y-axis because the x-coordinate of every point on the line is .
∴ Statement 1 is true.
For equations of the form x = ± k.
These represent vertical lines (parallel to the y-axis) because the value of x remains constant at k or -k for all values of y.
∴ Statement 2 is true.
∴ Both the statements are true.
Hence, option 1 is the correct option.
Answered By
1 Like
Related Questions
Line x - 5 = 0 and y + 3 = 0 intersect each other at point:
(5, 3)
(5, -3)
(-5, 3)
(-5, -3)
For the line 4x - 7y + 6 = 0 if x = 2; the value of y is :
2
-2
1
-1
Statement 1: The lines of the form ax ± by = 0 always pass through the origin.
Statement 2: On substituting x = 0 and y = 0; we get a x 0 ± b x 0 = 0.
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Assertion (A): y + 5 = 0 is the equation of line parallel to x-axis and at the distance of 5 unit in the negative direction from it.
Reason (R): For all the points on the y = a (a constant), the value of abscissa is a.
A is true, but R is false.
A is false, but R is true.
Both A and R are true, and R is the correct reason for A.
Both A and R are true, and R is the incorrect reason for A.