Mathematics
Statement 1: The lines of the form ax ± by = 0 always pass through the origin.
Statement 2: On substituting x = 0 and y = 0; we get a x 0 ± b x 0 = 0.
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Graphical Solution
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Answer
A line passes through the origin (0, 0) if the coordinates of the origin satisfy the equation of the line.
Substituting x = 0 and y = 0 in L.H.S. of the equation ax ± by = 0, we get :
⇒ a(0) ± b(0)
⇒ 0, which is equal to R.H.S.
Since, (0, 0) satisfies the equation ax ± by = 0, thus lines of the form ax ± by = 0 always pass through the origin.
∴ Both the statements are true.
Hence, option 1 is the correct option.
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Related Questions
For the line 4x - 7y + 6 = 0 if x = 2; the value of y is :
2
-2
1
-1
Statement 1: The graph of 2x - 5 = 0 is a line parallel to y-axis.
Statement 2: When the equations of line are of the form x = ± k (a constant), the lines are parallel to y-axis.
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Assertion (A): y + 5 = 0 is the equation of line parallel to x-axis and at the distance of 5 unit in the negative direction from it.
Reason (R): For all the points on the y = a (a constant), the value of abscissa is a.
A is true, but R is false.
A is false, but R is true.
Both A and R are true, and R is the correct reason for A.
Both A and R are true, and R is the incorrect reason for A.
Assertion (A): For the line 3x + 4y = 7, the abscissa is .
Reason (R): 3x + 4y = 7
⇒ 3x = 7
and x = .
A is true, but R is false.
A is false, but R is true.
Both A and R are true, and R is the correct reason for A.
Both A and R are true, and R is the incorrect reason for A.