Chemistry
A student prepared a Potassium sulphite solution in the lab and added few drops of barium nitrate solution to it. He observed a white precipitate being formed in the test tube. On addition of dilute hydrochloric acid to the white precipitate and mixing it, he observed that the precipitate disappeared.
(a) Name the white precipitate.
(b) Write a balanced chemical equation for the reaction between dilute hydrochloric acid and the white precipitate.
(c) Name the gas evolved in the above reaction.
Answer
(a) When the student mixed potassium sulphite solution (K2SO3) with barium nitrate (Ba(NO3)2), the white precipitate of Barium sulphite (BaSO3) is formed.
K2SO3 + Ba(NO3)2 ⟶ BaSO3 + 2KNO3
(b) When white precipitate of BaSO3 reacts with dilute HCl, it dissolves, forming barium chloride (BaCl2), water, and sulphur dioxide (SO2) gas.
BaSO3 + 2HCl ⟶ BaCl2 + H2O + SO2 ↑
(c) From the above reaction, the gas produced is sulphur dioxide (SO2).
Related Questions
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(a) Identify compound P.
(b) Give the chemical formula of Z.
(c) Write the reaction taking place between the identified compound P and sulphuric acid.
(d) Name compound Y.
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Element Electronic configuration Ionisation energy kjmol-1 X 2,2 900 Y 2,8,2 738 Z 2,8,8,2 590 (a) Explain why element X has highest ionisation energy.
(b) To which period does Z belong?
(c) Draw the electron dot structure of the compound formed between Z and oxygen.
The empirical formula of a hydrocarbon is C2H3. The hydrocarbon has a relative molecular mass of 54. (At wt: H = 1, C = 12)
(a) What is the molecular formula of the hydrocarbon?
(b) Draw the structural formula of the hydrocarbon.
(c) Give the general formula of the hydrocarbon.
Study the given figure and answer the given questions:
(a) Identify the application of electrolysis demonstrated above.
(b) Which metal is protected in the above process?
(c) Why should the metal be protected?