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Mathematics

Subtract:

(i) 3a - 2b + 4c from 5a - 3b - 5c

(ii) 5x2 - 3xy - 7y2 from 3x2 - xy - 2y2

(iii) 3p3 - 5p2q + 2q2 from q2 + p2q - 4p3

(iv) ab - bc - ca from 3ab + 2bc - 4ca

(v) 3z3 - 2z2 + 7z - 8 from 8 - z - z2

(vi) 2abc - a2 - b2 from b2 + a2 - 2abc

Algebraic Expressions

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Answer

(i) 3a - 2b + 4c from 5a - 3b - 5c

We have:

5a3b5c+3a2b+4c3a+2ab9c\begin{array}{rcccc} 5a & - & 3b & - & 5c \\ +3a & - & 2b & + & 4c \\ -\phantom{3a} & + & & - \\ \hline 2a & - & b & - & 9c \\ \hline \end{array}

Hence, the answer is 2a - b - 9c

(ii) 5x2 - 3xy - 7y2 from 3x2 - xy - 2y2

We have:

3x2xy2y2+5x23xy7y25x2++2x2+2xy+5y2\begin{array}{rcccc} 3x^2 & - & xy & - & 2y^2 \\ +5x^2 & - & 3xy & - & 7y^2 \\ -\phantom{5x^2} & + & & + \\ \hline -2x^2 & + & 2xy & + & 5y^2 \\ \hline \end{array}

Hence, the answer is -2x2 + 2xy + 5y2

(iii) 3p3 - 5p2q + 2q2 from q2 + p2q - 4p3

Arranging the terms to match (p3, p2q, q2):

4p3+p2q+q2+3p35p2q+2q23p3+7p3+6p2qq2\begin{array}{rcc} -4p^3 & + & p^2q & + & q^2 \\ +3p^3 & - & 5p^2q & + & 2q^2 \\ -\phantom{3p^3} & + & & - \\ \hline -7p^3 & + & 6p^2q & - & q^2 \\ \hline \end{array}

Hence, the answer is -7p3 + 6p2q - q2

(iv) ab - bc - ca from 3ab + 2bc - 4ca

Arranging the terms to match(ab, bc, ca):

3ab+2bc4ca+abbccaab++2ab+3bc3ca\begin{array}{rcccc} 3ab & + & 2bc & - & 4ca \\ +ab & - & bc & - & ca \\ -\phantom{ab} & + & & + \\ \hline 2ab & + & 3bc & - & 3ca \\ \hline \end{array}

Hence, the answer is 2ab + 3bc - 3ca

(v) 3z3 - 2z2 + 7z - 8 from 8 - z - z2

Arranging the expressions in ascending powers of z and use 0 as a placeholder for any missing terms:

8zz2+08+7z2z2+3z3+8+168z+z23z3\begin{array}{rcccccc} 8 & - & z & - & z^2 & + & 0 \\ -8 & + & 7z & - & 2z^2 & + & 3z^3 \\ +\phantom{8} & - & & + & & - \\ \hline 16 & - & 8z & + & z^2 & - & 3z^3 \\ \hline \end{array}

Hence, the answer is 16 - 8z + z2 - 3z3

(vi) 2abc - a2 - b2 from b2 + a2 - 2abc

Arranging the terms to match (a2, b2, abc):

a2+b22abca2b2+2abc+a2+2a2+2b24abc\begin{array}{rcc} a^2 & + & b^2 & - & 2abc \\ -a^2 & - & b^2 & + & 2abc \\ +\phantom{a^2} & + & & - \\ \hline 2a^2 & + & 2b^2 & - & 4abc \\ \hline \end{array}

Hence, the answer is 2a2 + 2b2 - 4abc

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