Subtract hexa-decimal number (A68D)₁₆ from (D53F)₁₆

$\begin{matrix} & \overset{C}{\cancel{D}} & \overset{4}{\cancel{5}} & 3 & F \ - & A & 6 & 8 & D \ \hline & \bold{2} & \bold{E} & \bold{B} & \bold{2} \end{matrix}$

Therefore, (D53F)₁₆ - (A68D)₁₆ = (2EB2)₁₆

Explanation

1. F - D = 15 - 13 = 2.
2. 3 - 8, here 8 is greater than 3 so we borrow 1 from next significant digit 5 and it becomes 4. Now 3 becomes 3 + 16 = 19 and 19 - 8 = 11 or B.
3. 4 - 6, here again 6 is greater than 4 so we borrow 1 from next significant digit D and it becomes C. Now 4 becomes 4 + 16 = 20 and 20 - 6 = 14 or E.
4. C - A = 12 - 10 = 2.