Subtract hexa-decimal number (ABCD)₁₆ from (EA9C)₁₆

$\begin{matrix} & \overset{D}{\cancel{E}} & \overset{9}{\cancel{A}} & \overset{8}{\cancel{9}} & C \ - & A & B & C & D \ \hline & \bold{3} & \bold{E} & \bold{C} & \bold{F} \end{matrix}$

Therefore, (EA9C)₁₆ - (ABCD)₁₆ = (3ECF)₁₆

Explanation

1. C - D = 12 - 13, as 13 is greater than 12 so we borrow 1 from next significant digit 9 and it becomes 8. Now 12 becomes 12 + 16 = 28 and 28 - 13 = 15 or F.
2. 8 - C = 8 - 12, as 12 is greater than 8 so we borrow 1 from next significant digit A and it becomes 9. Now 8 becomes 8 + 16 = 24 and 24 - 12 = 12 or C.
3. 9 - B = 9 - 11, as 11 is greater than 9 so we borrow 1 from next significant digit E and it becomes D. Now 9 becomes 9 + 16 = 25 and 25 - 11 = 14 or E.
4. D - A = 13 - 10 = 3.