Mathematics
Subtract the sum of 5y2 + y - 3 and y2 - 3y + 7 from 6y2 + y - 2.
Algebraic Expressions
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Answer
The sum of 5y2 + y - 3 and y2 - 3y + 7
5y2 + y - 3 + (y2 - 3y + 7)
= 5y2 + y - 3 + y2 - 3y + 7
Arrange the polynomial with like terms together and combine them.
= (5y2 + y2) + (y - 3y) + (- 3 + 7)
= 6y2 - 2y + 4
The difference of 6y2 - 2y + 4 from 6y2 + y - 2
= 6y2 + y - 2 - (6y2 - 2y + 4)
= 6y2 + y - 2 - 6y2 + 2y - 4
= (6y2 - 6y2) + (y + 2y) + (- 2 - 4)
= 0 + 3y - 6
Hence, the result is 3y - 6.
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