Sunita is 24 years older than her daughter Kavita. 6 years ago, Sunita was thrice as old as Kavita. Find their present ages.
Linear Eqns One Variable
1 Like

Question

Sunita is 24 years older than her daughter Kavita. 6 years ago, Sunita was thrice as old as Kavita. Find their present ages.

KnowledgeBoat · Accepted Answer

Let Kavita's present age be x years. Then, Sunita's present age = (x + 24) years. 6 years ago: Kavita's age = (x - 6) years. Sunita's age = (x + 24 - 6) years = (x + 18) years. According to the question, 6 years ago, Sunita was thrice as old as Kavita: x + 18 = 3(x - 6) ⇒ x + 18 = 3x - 18 ⇒ 18 + 18 = 3x - x [Transposing +x to RHS and -18 to LHS] ⇒ 36 = 2x ⇒ x = ⇒ x = 18 Kavita's present age = x years = 18 years. Sunita's present age = (x + 24) years = (18 + 24) years = 42 years. Hence, Sunita's present age is 42 years and Kavita's present age is 18 years.

Mathematics

Sunita is 24 years older than her daughter Kavita. 6 years ago, Sunita was thrice as old as Kavita. Find their present ages.

Linear Eqns One Variable

Related Questions

A man is twice as old as his son. 20 years ago, the age of the man was 12 times the age of the son. Find their present ages.

A man is 28 years older than his son. After 10 years, he will be thrice as old as his son. Find their present ages.

Divide 184 into two parts such that one-third of one part may exceed one-seventh of the other part by 8.

A sum of ₹ 500 is in the form of denominations of ₹ 5 and ₹ 10. If the total number of notes is 90, find the number of notes of each type.