Sunita is 24 years older than her daughter Kavita. 6 years ago, Sunita was thrice as old as Kavita. Find their present ages.
Linear Eqns One Variable
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Question

Sunita is 24 years older than her daughter Kavita. 6 years ago, Sunita was thrice as old as Kavita. Find their present ages.

KnowledgeBoat · Accepted Answer

Let Kavita's present age be x years. Then, Sunita's present age = (x + 24) years. 6 years ago: Kavita's age = (x - 6) years. Sunita's age = (x + 24 - 6) years = (x + 18) years. According to the question, 6 years ago, Sunita was thrice as old as Kavita: x + 18 = 3(x - 6) ⇒ x + 18 = 3x - 18 ⇒ 18 + 18 = 3x - x [Transposing +x to RHS and -18 to LHS] ⇒ 36 = 2x ⇒ x = ⇒ x = 18 Kavita's present age = x years = 18 years. Sunita's present age = (x + 24) years = (18 + 24) years = 42 years. Hence, Sunita's present age is 42 years and Kavita's present age is 18 years.

Mathematics

Sunita is 24 years older than her daughter Kavita. 6 years ago, Sunita was thrice as old as Kavita. Find their present ages.

Linear Eqns One Variable

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