Which term of the G.P. 2, 8, 32, 128, ........ is 131072? 1. 9th 2. 10th 3. 8th 4. 12th

Question

KnowledgeBoat · Accepted Answer

In the given G.P., a = 2 r = = 4 We know that, Tn = arn - 1 Let nth term be 131072. ⇒ Tn = 131072 ⇒ 2.(4)n - 1 = 131072 ⇒ (22)n - 1 = ⇒ 22n - 2 = 65536 ⇒ 22n - 2 = 216 Equate exponents: ⇒ 2n - 2 = 16 ⇒ 2n = 16 + 2 ⇒ 2n = 18 ⇒ n = = 9. Hence, option 1 is the correct option.

Mathematics

Which term of the G.P. 2, 8, 32, 128, …….. is 131072?
9th
10th
8th
12th

G.P.

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256
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Mathematics

Which term of the G.P. 2, 8, 32, 128, …….. is 131072?9th10th8th12th

G.P.

Related Questions

The 10th term of the G.P. 1, −a, a2, −a3, …….. is :a9−a10−a11−a9

If the 5th term of a G.P. is 2, then the product of its first nine terms is :25610245122048

Which term of the G.P. 2, 8, 32, 128, …….. is 131072?
9th
10th
8th
12th

The 10th term of the G.P. 1, −a, a², −a³, …….. is :
a⁹
−a¹⁰
−a¹¹
−a⁹

If the 5th term of a G.P. is 2, then the product of its first nine terms is :
256
1024
512
2048