The adjoining sketch shows a running track 3.5 m wide all around which consists of two straight paths and two semicircular rings. Find the area of the track.
Mensuration
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Question

The adjoining sketch shows a running track 3.5 m wide all around which consists of two straight paths and two semicircular rings. Find the area of the track.

KnowledgeBoat · Accepted Answer

From figure, Length of inner rectangle ABCD = 140 m Breadth of inner rectangle ABCD = 42 m Diameter of inner semi-circle = 42 m Radius of inner semi-circle (r) = = 21 m. Length of outer rectangle = Length of inner rectangle = 140 m Breadth of outer rectangle = Breadth of inner rectangle + 2 × Width of outer track = 42 + 2 × 3.5 = 42 + 7 = 49 m. Diameter of outer semi-circle = 49 m Radius of outer semi-circle (R) = = 24.5 m. Area of track = Area of outer rectangle - Area of inner rectangle + 2(Area of outer semi-circle - Area of inner semi-circle) Hence, area of track = 1480.5 m².

Mathematics

The adjoining sketch shows a running track 3.5 m wide all around which consists of two straight paths and two semicircular rings. Find the area of the track.

Mensuration

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