The altitude of an isosceles triangle is 4 cm and its base is 2 cm more than its height. The area of the triangle is :

1. 24 cm²

2. 12 cm²

3. 16 cm²

4. 8 cm²

Given:

Altitude of the triangle = 4 cm

Base of the triangle = 2 cm more than its height

= 2 + 4 cm

= 6 cm

∵ As we know, the area of the triangle = $\dfrac{1}{2}$ x side x height

= $\dfrac{1}{2}$ x 6 x 4 cm²

= $\dfrac{1}{2}$ x 24 cm²

= 12 cm²

Hence, option 2 is the correct option.