The area of a rectangle is 640 m 2 . Taking its length as x m; find, in terms of x, the width of the rectangle. If the perimeter of the rectangle is 104 m; find its dimensions.

Given: Area of the rectangle = 640 m 2 Length = x cm Let `b` be the width of the rectangle. Area of the rectangle = l x b ⇒ x b = 640 ⇒ b = m Perimeter of the rectangle = 2(l + b) ⇒ 2 = 104 ⇒ ⇒ = 52 ⇒ x 2 + 640 = 52x ⇒ x 2 - 52x + 640 = 0 ⇒ x 2 - 30x - 20x + 640 = 0 ⇒ x(x - 30) - 20(x - 30) = 0 ⇒ (x - 30)(x - 20) = 0 ⇒ x = 30 or 20 Now, b = = or = 20 m or 32 m Hence, the width of rectangle is and the dimensions of the rectangle are 20 m and 32 m.

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Mathematics

The area of a rectangle is 640 m². Taking its length as x m; find, in terms of x, the width of the rectangle. If the perimeter of the rectangle is 104 m; find its dimensions.

Mensuration

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Mathematics

The area of a rectangle is 640 m2. Taking its length as x m; find, in terms of x, the width of the rectangle. If the perimeter of the rectangle is 104 m; find its dimensions.

Mensuration

Related Questions

For the trapezium given below; find its area.

The perimeter of a rectangular board is 70 cm. Taking its length as x cm, find its width in terms of x.If the area of the rectangular board is 300 cm2; find its dimensions.

The length of a rectangle is twice the side of a square and its width is 6 cm greater than the side of the square. If area of the rectangle is three times the area of the square; find the dimensions of each.

ABCD is a square with each side 12 cm. P is a point on BC such that area of Δ ABP : area of trapezium APCD = 1 : 5. Find the length of CP.

The area of a rectangle is 640 m². Taking its length as x m; find, in terms of x, the width of the rectangle. If the perimeter of the rectangle is 104 m; find its dimensions.

The perimeter of a rectangular board is 70 cm. Taking its length as x cm, find its width in terms of x.
If the area of the rectangular board is 300 cm²; find its dimensions.