The area of a rectangle is x^3 - 8x^2 + 7 and one of its sides is x - 1. Find the length of the adjacent side.

Area of the rectangle = x 3 \- 8x 2 \+ 7 One side = (x \- 1) As we know the area of rectangle = One side x Other side Other side = Area of rectangle ÷ One side = (x 3 \- 8x 2 \+ 7) ÷ (x \- 1) Hence, length of adjacent side is x 2 - 7x - 7.

Find the quotient and the remainder (if any), when:
3x⁴ + 6x³ - 6x² + 2x - 7 is divided by x - 3.

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Find the quotient and the remainder (if any), when:
6x² + x - 15 is divided by 3x + 5.

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(5x - 4y) - (5y - 4x) is equal to:
9(x - y)
x - y
(y - x)
0

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Mathematics

The area of a rectangle is x³ - 8x² + 7 and one of its sides is x - 1. Find the length of the adjacent side.

Algebraic Expressions

Related Questions

Find the quotient and the remainder (if any), when:
3x⁴ + 6x³ - 6x² + 2x - 7 is divided by x - 3.

Find the quotient and the remainder (if any), when:
6x² + x - 15 is divided by 3x + 5.

(5x - 4y) - (5y - 4x) is equal to:
9(x - y)
x - y
(y - x)
0

Mathematics

The area of a rectangle is x3 - 8x2 + 7 and one of its sides is x - 1. Find the length of the adjacent side.

Algebraic Expressions

Related Questions

Find the quotient and the remainder (if any), when:3x4 + 6x3 - 6x2 + 2x - 7 is divided by x - 3.

Find the quotient and the remainder (if any), when:6x2 + x - 15 is divided by 3x + 5.

(5x - 4y) - (5y - 4x) is equal to:9(x - y)x - y(y - x)0

The area of a rectangle is x³ - 8x² + 7 and one of its sides is x - 1. Find the length of the adjacent side.

Find the quotient and the remainder (if any), when:
3x⁴ + 6x³ - 6x² + 2x - 7 is divided by x - 3.

Find the quotient and the remainder (if any), when:
6x² + x - 15 is divided by 3x + 5.

(5x - 4y) - (5y - 4x) is equal to:
9(x - y)
x - y
(y - x)
0