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Mathematics

The area of the given figure is :

The area of the given figure is : Area and Perimeter of Plane Figures, Concise Mathematics Solutions ICSE Class 9.
  1. AC x BD

  2. 12×AC×BD\dfrac{1}{2}\times AC \times BD

  3. 12×AB×BD\dfrac{1}{2}\times AB \times BD

  4. 12×(AD+BC)×BD\dfrac{1}{2}\times (AD + BC) \times BD

Mensuration

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Answer

Area of triangle = 12\dfrac{1}{2} x base x height

For Δ ABD,

Area = 12\dfrac{1}{2} x BD x AO

For Δ CBD,

Area = 12\dfrac{1}{2} x BD x CO

Area of quadrilateral ABCD = Area of Δ ABD + Area of Δ CBD

= 12\dfrac{1}{2} x BD x AO + 12\dfrac{1}{2} x BD x CO

= 12\dfrac{1}{2} x BD x (AO + CO)

= 12\dfrac{1}{2} x BD x AC

Hence, option 2 is the correct option.

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