The compounded ratio of x - y : x + y and (x + y)2 : x2 - y2 is :
2 : 1
1 : (x + y)2
1 : 1
1 : 2
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Compounded ratio of x - y : x + y and (x + y)2 : x2 - y2 :
⇒x−yx+y×(x+y)2x2−y2⇒x−yx+y×(x+y)2(x+y)(x−y)⇒(x−y)(x+y)2(x+y)2(x−y)⇒11⇒1:1.\Rightarrow \dfrac{x - y}{x + y} \times \dfrac{(x + y)^2}{x^2 - y^2} \\[1em] \Rightarrow \dfrac{x - y}{x + y} \times \dfrac{(x + y)^2}{(x + y)(x - y)} \\[1em] \Rightarrow \dfrac{(x - y)(x + y)^2}{(x + y)^2(x - y)} \\[1em] \Rightarrow \dfrac{1}{1} \\[1em] \Rightarrow 1 : 1.⇒x+yx−y×x2−y2(x+y)2⇒x+yx−y×(x+y)(x−y)(x+y)2⇒(x+y)2(x−y)(x−y)(x+y)2⇒11⇒1:1.
Hence, Option 3 is the correct option.
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If (2x + 3y) : (3x + 2y) = 4 : 3; then x : y is :
6 : 1
2 : 3
1 : 6
3 : 2
Two numbers are in the ratio 5 : 8. If 10 is subtracted from each number, the ratio becomes 4 : 7. The numbers are :
80 and 40
50 and 80
25 and 40
40 and 25
The sub-duplicate ratio of 6x2 : 24y2 is :
x : 2y
2x : y
x : y
y : x
If m+nm+3n=23\dfrac{m + n}{m + 3n} = \dfrac{2}{3}m+3nm+n=32, find : 2n23m2+mn\dfrac{2n^2}{3m^2 + mn}3m2+mn2n2.
