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Mathematics

The given distribution shows the number of runs scored by some top batsmen of the world in one-day international cricket matches.

Runs scoredNumber of batsmen
3000 - 40004
4000 - 500018
5000 - 60009
6000 - 70007
7000 - 80006
8000 - 90003
9000 - 100001
10000 - 110001

Find the mode of the data.

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Answer

By formula,

Mode = l + (f1f02f1f0f2)×h\Big(\dfrac{f1 - f0}{2f1 - f0 - f_2}\Big) \times h

Here,

  1. Class size is h.

  2. The lower limit of modal class is l

  3. The Frequency of modal class is f1.

  4. Frequency of class preceding modal class is f0.

  5. Frequency of class succeeding the modal class is f2.

Class 4000 - 5000 has the highest frequency.

∴ It is the modal class.

∴ l = 4000, f1 = 18, f0 = 4, f2 = 9 and h = 1000.

Substituting values we get :

Mode=4000+(1842×1849)×1000=4000+143613×1000=4000+1400023=4000+608.7=4608.7\text{Mode} = 4000 + \Big(\dfrac{18 - 4}{2 \times 18 - 4 - 9}\Big) \times 1000 \\[1em] = 4000 + \dfrac{14}{36 - 13} \times 1000 \\[1em] = 4000 + \dfrac{14000}{23} \\[1em] = 4000 + 608.7 \\[1em] = 4608.7

Hence, mode = 4608.7 runs.

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