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Mathematics

The following distribution gives the state-wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.

Number of student per teacherNumber of states/U.T.
15 - 203
20 - 258
25 - 309
30 - 3510
35 - 403
40 - 450
45 - 500
50 - 552

Statistics

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Answer

By formula,

Mode = l + (f1f02f1f0f2)×h\Big(\dfrac{f1 - f0}{2f1 - f0 - f_2}\Big) \times h

Here,

  1. Class size is h.

  2. The lower limit of modal class is l

  3. The Frequency of modal class is f1.

  4. Frequency of class preceding modal class is f0.

  5. Frequency of class succeeding the modal class is f2.

Class 30 - 35 has the highest frequency.

∴ It is the modal class.

∴ l = 30, f1 = 10, f0 = 9, f2 = 3 and h = 5.

Substituting values we get :

Mode=30+(1092×1093)×5=30+12012×5=30+58=30+0.625=30.62530.6\text{Mode} = 30 + \Big(\dfrac{10 - 9}{2 \times 10 - 9 - 3}\Big) \times 5 \\[1em] = 30 + \dfrac{1}{20 - 12} \times 5 \\[1em] = 30 + \dfrac{5}{8} \\[1em] = 30 + 0.625 \\[1em] = 30.625 ≈ 30.6

We will find mean using direct method.

Number of student per teacherNumber of states/U.T. (fi)Class mark (xi)fixi
15 - 20317.552.5
20 - 25822.5180
25 - 30927.5247.5
30 - 351032.5325
35 - 40337.5112.5
40 - 45042.50
45 - 50047.50
50 - 55252.5105
TotalΣfi = 35Σfixi = 1022.5

By formula,

Mean = ΣfixiΣfi=1022.535\dfrac{Σfixi}{Σf_i} = \dfrac{1022.5}{35} = 29.2

Hence, mode = 30.6 and median = 29.2 so, most states/U.T. have a student teacher ratio of 30.6 and on an average, this ratio is 29.2

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