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Mathematics

The following data gives the information on the observed lifetimes (in hours) of 225 electrical components :

Lifetime (in hours)Frequency
0 - 2010
20 - 4035
40 - 6052
60 - 8061
80 - 10038
100 - 12029

Determine the modal lifetimes of the components.

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Answer

By formula,

Mode = l + (f1f02f1f0f2)×h\Big(\dfrac{f1 - f0}{2f1 - f0 - f_2}\Big) \times h

Here,

  1. Class size is h.

  2. The lower limit of modal class is l

  3. The Frequency of modal class is f1.

  4. Frequency of class preceding modal class is f0.

  5. Frequency of class succeeding the modal class is f2.

Class 60 - 80 has the highest frequency.

∴ It is the modal class.

∴ l = 60, f1 = 61, f0 = 52, f2 = 38 and h = 20.

Substituting values we get :

Mode=60+(61522×615238)×20=60+912290×20=60+18032=60+5.625=65.625\text{Mode} = 60 + \Big(\dfrac{61 - 52}{2 \times 61 - 52 - 38}\Big) \times 20 \\[1em] = 60 + \dfrac{9}{122 - 90} \times 20 \\[1em] = 60 + \dfrac{180}{32} \\[1em] = 60 + 5.625 \\[1em] = 65.625

Hence, modal lifetime = 65.625 hours.

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