Physics

The pressure inside a liquid of density ρ at a depth h is:

  1. hρg\text {hρg}
  2. hρg\dfrac{\text h}{\text {ρg}}
  3. g\dfrac{\text {hρ}}{\text g}
  4. \text {hρ}

Fluids Pressure

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Answer

hρg

Reason — The three factors on which the pressure at a point in a liquid depends are —

  1. depth of the point below the free surface (h)

  2. density of liquid (ρ) and

  3. acceleration due to gravity (g)

Pressure = hρg

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