The roots of the quadratic equation x2 - 3x - 4 = 0 are
-4, 1
4, -1
4, 1
-4, -1
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Substituting 4 in x2 - 3x - 4 = 0 we get,
⇒ 42 - 3(4) - 4
⇒ 16 - 12 - 4
⇒ 16 - 16
⇒ 0.
Substituting -1 in x2 - 3x - 4 = 0 we get,
⇒ (-1)2 - 3(-1) - 4
⇒ 1 + 3 - 4
⇒ 4 - 4
Hence,Option 2 is the correct option.
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Which of the following quadratic equations has -1 as a root ?
x2 + 5x + 6 = 0
2x2 - 3x + 1 = 0
2x2 + x - 3 = 0
2x2 - x - 3 = 0
Solve the following equation:
x(2x + 5) = 3
3x2 - 4x - 4 = 0