Mathematics
Three vertices of a square ABCD are A(2, 0), B(-3, 0) and C(-3, -5). Its fourth vertex D is:
(2, 5)
(2, -5)
(-2, 5)
(-2, -5)
Coordinate Geometry
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Answer
The points are shown on the graph below:
Steps of construction :
Plot points A(2, 0), B(-3, 0) and C(-3, -5) on graph.
Measure AB.
Mark point D such that it is at a distance AB from points A and C.
Join AB, BC, CD and DA.
From graph,
The co-ordinates of fourth vertex D is (2, -5).
Hence, option 2 is the correct option.
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Related Questions
If the perpendicular distance of a point P from the x-axis is 5 unit then the point P has
x-co-ordinate = -5
y-co-ordinate = 5 only
y-co-ordinate = -5 only
y-co-ordinate = 5 or -5
A point lies on y-axis at a distance of 2 unit from x-axis. Its co-ordinates are :
(2, 0) only
(0, 2) only
(2, 2)
(0, 2) or (0, -2)
Statement 1: In the given diagram, OAB is an equilateral triangle.
Co-ordinates of the vertex B = (4, 4)
Statement 2: B = (4, )
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Statement 1: The vertex B of square OABC with each side 4 units lies in the fourth quadrant and its side are along the co-ordinate axes. The co-ordinate of vertex B are (4, -4).
Statement 2: B = (4, 4)
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.