Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3? 1. 2. 3. 4.

Question

KnowledgeBoat · Accepted Answer

The tickets are numbered from 1 to 20. Total number of outcomes = 20 Let E be the event of getting a number multiple of 3, then E = {3, 6, 9, 12, 15, 18} The number of favorable outcomes to the event E = 6 P(E) = Hence, option 3 is the correct option.

Mathematics

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3? 1. 2. 3. 4.

Probability

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