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Two adjacent sides of a parallelogram are 36 cm and 25 cm. If the distance between longer sides is 15 cm, find the distance between the shorter sides.

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Answer

Let ABCD be a parallelogram with side AB = 36 cm and side BC = 25 cm.

Two adjacent sides of a parallelogram are 36 cm and 25 cm. If the distance between longer sides is 15 cm, find the distance between the shorter sides. ARC Properties of Circle, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

Distance between longer side DM = 15 cm

Consider DN as the distance between the shorter sides.

Area of parallelogram ABCD = base × height

= AB × DM = 36 × 15 = 540 cm2.

Considering base BC and height DN.

Area of parallelogram ABCD = BC × DN

⇒ 540 = 25 × DN

⇒ DN = 54025\dfrac{540}{25} = 21.6 cm.

Hence, the distance between shorter sides = 21.6 cm.

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