Physics
Two forces each of magnitude 10N act vertically upwards and downwards respectively at the two ends A and B of a uniform rod of length 4m which is pivoted at its mid-point O as shown. Determine the magnitude of resultant moment of forces about the pivot O.
Force
232 Likes
Answer
Given,
Ab = 4m
OA = 2m
OB = 2m
Force at A = 10N
Force at B = 10N
As we know ,
Moment of force = F x r
Substituting the values of F and r
Moment of force about o at point A
Moment of force about o at point B
Total moment of forces about the centre O
Total moment of force about the pivot O is 40 Nm (clockwise)
Answered By
155 Likes
Related Questions
A steering wheel of diameter 0.5m is rotated anti-clockwise by applying two forces each of magnitude 6N. Draw a diagram to show the application of forces and calculate the moment of forces applied.
The diagram shows two forces F1 = 5N and F2 = 3N acting at points A and B of a rod pivoted at a point O, such that OA = 2m and OB = 4m
Calculate:
(i) the moment of force F1 about O.
(ii) the moment of force F2 about O.
(iii) total moment of the two forces about O.
Figure shows two forces each of magnitude 10N acting at the points A and B at a separation of 50 cm, in opposite directions. Calculate the resultant moment of the two forces about the point (i) A, (ii) B and (iii) O, situated exactly at the middle of the two forces.
A 55 kg student is climbing a rope ladder hanging from a helicopter. While climbing, the student leans 0.35 m backward from the vertical line of the ladder.
(i) Calculate the torque produced about the top support point of the rope ladder due to the student's weight. [Take g = 10 m s-2]
(ii) Explain why the ladder starts swinging when the student leans backward and how the student should climb to minimize the swinging.