Two poles of heights 6 m and 11 m stand vertically on a plane ground. If the distance between their feet is 12 m; find the distance between their tips.
Pythagoras Theorem
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Question

Two poles of heights 6 m and 11 m stand vertically on a plane ground. If the distance between their feet is 12 m; find the distance between their tips.

KnowledgeBoat · Accepted Answer

Let AB and CD be two poles of height 6 m and 11 m respectively. From figure, ABDE is a rectangle. ∴ AE = BD = 12 m and ED = AB = 6 m. From figure, CE = CD - ED = 11 - 6 = 5 m. In right-angled triangle, By pythagoras theorem, ⇒ (Hypotenuse)² = (Perpendicular)² + (Base)² ⇒ AC² = CE² + AE² ⇒ AC² = 5² + 12² ⇒ AC² = 25 + 144 ⇒ AC² = 169 ⇒ AC = = 13 m. Hence, the distance between the tips of two poles is 13 m.

Mathematics

Two poles of heights 6 m and 11 m stand vertically on a plane ground. If the distance between their feet is 12 m; find the distance between their tips.

Pythagoras Theorem

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Mathematics

Two poles of heights 6 m and 11 m stand vertically on a plane ground. If the distance between their feet is 12 m; find the distance between their tips.

Pythagoras Theorem

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In triangle ABC,
AB = AC = x; BC = 10 cm and the area of the triangle is 60 cm². Find x.

In △ ABC, ∠C = 90° and AC = BC, then AB² is equal to :
AC²
2AC²
BC²
2BC² - AC²

In the given diagram, AE² + BD² is equal to :
AB² - DE²
DE² - AB²
AB² + DE²
DE × AB