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Mathematics

By using a ruler and compass, construct an angle of 135° and bisect it. Measure any one part by protractor and see how accurate you are.

Constructions

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Answer

Steps:

  1. Draw a straight line AOA'.

  2. Construct a perpendicular OC to line AOA' at O. Then ∠AOC = 90°.

  3. Bisect ∠A'OC by drawing two equal arcs from centre O, cutting line OA' at point D and OC at point E. Now, from points D and E draw two arcs of equal length (>12ED)\left(\gt\dfrac{1}{2} \text{ED}\right) intersecting each other at point B. Join OB and OB is the bisector of ∠A'OC. Then ∠COB = 45°.

  4. Therefore, ∠AOB = ∠AOC + ∠COB = 90° + 45° = 135°.

  5. Now bisect ∠AOB. With O as centre, draw two equal arcs that cut OA at point P and OB at point Q.

  6. With P and Q as centres and equal radii (>12PQ)\left(\gt\dfrac{1}{2} \text{PQ}\right), draw two arcs cutting each other at R.

  7. Join OR and produce it to form ray OR.

By using a ruler and compass, construct an angle of 135° and bisect it. Measure any one part by protractor and see how accurate you are. Practical Geometry (Constructions), ML Aggarwal Understanding Mathematics Solutions ICSE Class 6.

Then OR is the bisector of ∠AOB.

On measuring one of the parts with a protractor, we find:

∠AOR = 67.5° (and ∠ROB = 67.5°).

Hence, ray OR bisects ∠AOB into two equal parts of 67.5° each.

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