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Mathematics

Using step-deviation method, find mean for the following frequency distribution

ClassFrequency
0-153
15-304
30-457
45-606
60-758
75-902

Statistics

ICSE Sp 2025

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Answer

In the given table i is the class interval which is equal to 15.

ClassClass mark (x)d = (x - A)u = d/iFrequency (f)fu
0-157.5-45-33-9
15-3022.5-30-24-8
30-4537.5-15-17-7
45-60A = 52.50060
60-7567.515188
75-9082.530224
TotalΣf = 30Σfu = -12

Mean = A + ΣfuΣf×i=52.5+1230×15\dfrac{Σfu}{Σf} \times i = 52.5 + \dfrac{-12}{30} \times 15

= 52.51803052.5 - \dfrac{180}{30}

= 52.5 - 6

= 46.50

Hence, mean = 46.50

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