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Mathematics

Without solving, comment upon the nature of roots of the following equation :

25x2 - 10x + 1 = 0

Quadratic Equations

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Answer

Comparing 25x2 - 10x + 1 = 0 with ax2 + bx + c = 0 we get,

a = 25, b = -10 and c = 1.

We know that,

Discriminant = D = b2 - 4ac = (-10)2 - 4(25)(1)

= 100 - 100 = 0;

Since, a, b and c are real numbers; a ≠ 0 and b2 - 4ac = 0

∴ The roots are real and equal.

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