Mathematics
Without solving, comment upon the nature of roots of the following equation :
6x2 - 13x + 4 = 0
Quadratic Equations
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Answer
Comparing 6x2 - 13x + 4 = 0 with ax2 + bx + c = 0 we get,
a = 6, b = -13 and c = 4.
We know that,
Discriminant = D = b2 - 4ac = (-13)2 - 4(6)(4)
= 169 - 96 = 73; which is positive.
Since, a, b and c are real numbers; a ≠ 0 and b2 - 4ac > 0
∴ The roots are real and unequal.
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