Write a pair of irrational numbers whose product is irrational.

Let $\sqrt{2} \text{ and } \sqrt{3}$ be two irrational numbers.

Product of numbers

$= \sqrt{2} \times \sqrt{3} \\[1em] = \sqrt{6}.$

$\sqrt{6}$ is an irrational number.

Hence, required pair = $\sqrt{2} \text{ and } \sqrt{3}$.