Write down the equation of the line passing through (-3, 2) and perpendicular to the line 3y = 5 - x.

Given equation of the line is, ⇒ 3y = 5 - x ⇒ y = Comparing with y = mx + c we get, Slope (m 1 ) = . Let slope of the line perpendicular to the given line be m 2 . ∴ m 1 × m 2 = -1. Equation of the line having slope 3 and passing through (-3, 2) can be given by point-slope form i.e., Hence, the equation of the required line is 3x - y + 11 = 0.