Given,
⇒ x = a b a − b a + b Taking log on Both sides, ⇒ log x = log ( a b a − b a + b ) ⇒ log x = log a b + log a − b a + b ⇒ log x = log a + log b + log ( a − b a + b ) 1 2 ⇒ log x = log a + log b + 1 2 log a − b a + b ⇒ log x = log a + log b + 1 2 [ log ( a − b ) − log ( a + b ) ] \Rightarrow x = ab \sqrt{\dfrac{a - b}{a + b}} \\[1em] \text{Taking log on Both sides,} \\[1em] \Rightarrow \log \space x = \log \space \Big(ab \sqrt{\dfrac{a - b}{a + b}}\Big) \\[1em] \Rightarrow \log \space x = \log \space ab + \log \space\sqrt{\dfrac{a - b}{a + b}} \\[1em] \Rightarrow \log \space x = \log \space a + \log \space b + \log \space \Big({\dfrac{a - b}{a + b}}\Big)^{\dfrac{1}{2}} \\[1em] \Rightarrow \log \space x = \log \space a + \log \space b + \dfrac{1}{2} \log \space {\dfrac{a - b}{a + b}} \\[1em] \Rightarrow \log \space x = \log \space a + \log \space b + \dfrac{1}{2} [\log \space ({a - b}) - \log \space ({a + b})] \\[1em] ⇒ x = ab a + b a − b Taking log on Both sides, ⇒ log x = log ( ab a + b a − b ) ⇒ log x = log ab + log a + b a − b ⇒ log x = log a + log b + log ( a + b a − b ) 2 1 ⇒ log x = log a + log b + 2 1 log a + b a − b ⇒ log x = log a + log b + 2 1 [ log ( a − b ) − log ( a + b )]
Hence, logarithmic equation is
log x = log a + log b + 1 2 [ log ( a − b ) − log ( a + b ) ] \log \space x = \log \space a + \log \space b + \dfrac{1}{2} [\log \space ({a - b}) - \log \space ({a + b})] log x = log a + log b + 2 1 [ log ( a − b ) − log ( a + b )]