Mathematics
x ∈ W, x ≥ -3 and x < 5.
Statement (1) : There will be no solution for the given inequalities.
Statement (2) : The real number line for the given inequations is :
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Linear Inequations
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Answer
Statement 1 is false, and statement 2 is true.
Reason
x ≥ -3
Solution set of x = {-3, -2, -1, 0, 1, 2, ……….} ………. (1)
And, x < 5
Solution set of x = {………., 1, 2, 3, 4} ………. (2)
From (1) and (2), we get
Solution set = {-3, -2, -1, 0, 1, 2, 3, 4}
So, statement 1 is false.
The real number for the given inequations is :
So, statement 2 is true.
Hence, option 4 is correct.
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Related Questions
where x ∈ R.
Assertion (A): The largest value of x is .
Reason (R): When the signs of both the sides of an inequalities are changed, the sign of inequality reverses.
A is true, R is false.
A is false, R is true.
Both A and R are true and R is the correct reason for A.
Both A and R are true and R is the incorrect reason for A.
Inequation 5 - 2x ≥ x - 10, where x ∈ N (Natural numbers)
Assertion (A): 5 - 2x ≥ x - 10 ⇒ -3x ≥ -15 ⇒ x ≥ 5
∴ Solution set = {5, 6, 7, 8, ……….}
Reason (R): 5 - 2x ≥ x - 10 ⇒ 5 + 10 ≥ 3x ⇒ x ≤ 5
∴ Solution set = {1, 2, 3, 4, 5}
A is true, R is false.
A is false, R is true.
Both A and R are true and R is correct reason for A.
Both A and R are true and R is incorrect reason for A.
5 + x ≤ 2x < x - 2, x ∈ R.
Statement (1) : There is no value of x ∈ R that satisfies the given inequation.
Statement (2) : 5 + x - x ≤ 2x - x < x - 2 - x ⇒ 5 ≤ x < -2
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Solve the inequation :
and x ∈ R.