(x² + 3x) men can do a piece of work in (x² - 2x) days, then one day work of 1 man is : 1. 2. (x² + 3x)(x² - 2x) 3. 4. none of these

Given, total number of men = (x2 + 3x) Total number of days = (x2 - 2x) Total work = (x2 + 3x)(x2 - 2x) One day work of 1 man = Hence, option 4 is the correct option.

Mathematics

(x² + 3x) men can do a piece of work in (x² - 2x) days, then one day work of 1 man is :
$\dfrac{x + 3}{x - 2}$
(x² + 3x)(x² - 2x)
$\dfrac{x - 2}{x + 3}$
none of these

Factorisation

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Answer

Given, total number of men = (x² + 3x)

Total number of days = (x² - 2x)

Total work = (x² + 3x)(x² - 2x)

One day work of 1 man = $\dfrac{1}{(x^2 + 3x)(x^2 - 2x)}$

Hence, option 4 is the correct option.

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Mathematics

(x2 + 3x) men can do a piece of work in (x2 - 2x) days, then one day work of 1 man is :x+3x−2\dfrac{x + 3}{x - 2}x−2x+3​(x2 + 3x)(x2 - 2x)x−2x+3\dfrac{x - 2}{x + 3}x+3x−2​none of these

Factorisation

Answer

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(x² + 3x) men can do a piece of work in (x² - 2x) days, then one day work of 1 man is :
$\dfrac{x + 3}{x - 2}$
(x² + 3x)(x² - 2x)
$\dfrac{x - 2}{x + 3}$
none of these

(3a - 1)² - 6a + 2 is equal to:
(3a - 1)(a - 1)
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(3a - 1)(a + 1)
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$\dfrac{1}{3}$ x² - 2x - 9 is equal to:
$\dfrac{1}{3}$ (x - 9)(x + 3)
$\dfrac{1}{3}$ (x - 9)(x - 3)
$\dfrac{1}{3}$ (x + 9)(x - 3)
$\dfrac{1}{3}$ (x + 9)(x + 3)